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At time t = 0 s, voltage of an A.C. generator starts from 0 V and becomes 2V at time t = 1/(100pi)s.The voltage keeps on increasing up to 100 V, after which it starts to decrease. Find the frequency of the generator. |
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Answer» 2 Hz `therefore V=V_m SIN omegat` Now , `t=1/(100pi) RARR` from V=2V to V =100 V `therefore V_m` = 100 V Now, `V=V_m sin omegat` `therefore 2 = 100 sin (2pi ft)` `therefore 2/100=sin ((2pifxx1)/(100pi))` `therefore 1/50=sin(f/50)` If ANGLE is small then sin `(f/50) approx f/50` `therefore 1/50=f/50` `therefore` f=1 Hz |
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