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At time t = Os a particle starts moving along the x-direction. If its kinetic energy increases uniformly with time Y', the net force acting on it must be proportional to : |
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Answer» constant `1/2mv^2 prop t` or `1/2mv^2=kt`, where .k. is a constant. If p = MV is the linear MOMENTUM of the body,then `(p^2)/(2m)=kt` or `p=sqrt(2mk)xxt^(1/2)`or `F=(dp)/(dt)=sqrt(2mk)xx1/2xxt^(1/2)` or `F prop (1)/(sqrtt)`. |
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