1.

At two different places the angles of dip are respectively 30^(@) and 45^(@). At these two places the ratio of horizontal component of earth's magnetic field is

Answer»

`sqrt3 : sqrt2`
`1 : sqrt2`
`1 : 2`
`1 : sqrt3`

Solution :HORIZONTAL COMPONENT, `B_(H) = B_(e) costheta`
`therefore B_(H) = B_(e) cos^(30) and B_(H_(2)) = B_(e) cos45^(@)`
Thus, `B_(H_(1))/B_(H_(2))=(cos30^@)/(cos45^@)=(sqrt3/2)/(sqrt1/2)=sqrt3/sqrt2`


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