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At two points P and Q on a screen in Young's double slit experiment, waves from slits S_(1) and S_(2) have a path difference of 0 and (lambda)/(4) respectively. The ratio of intensities at P and Q will be |
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Answer» `2 : 1` `Delta PHI = 0^(@)` `I_(1)= I_(0) + I_(0) + 2I_(0)cos 0^(@) = 4I_(0)` `Deltax_(2) = (LAMBDA)/(4)` `Deltatheta = (2pi)/(lambda) (lambda)/(4) = ((pi)/(2))` `I_(2) = I_(0) + I_(0) + 2I_(0) cos (pi)/(2) = 2 I_(0)` `(I_(1))/(I_(2)) = (4I_(0))/(2I_(0)) = 2/1`. |
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