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At what angle should a ray of light be incident on the face of a prism of refracting angle 60^(@) so that it just suffers total internal reflection at the other face? The refractive index of the material of the prism is 1.524. |
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Answer» Solution :If the REFRACTED RAY in the PRISM is incident on the SECOND face at the critical angle i c , the angle of refraction r at the first face is `(60^(@)-i_(c))`. Now, `i_(c) = sin^(-1) (1//1.524) ~= 41^(@)` Therefore, `r = 19^(@) sin i = 0.4962, i ~= 30^(@)` |
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