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At what angle should a ray of light be incident on the face of a prism of refracting angle 60^(@) so that it just suffers total internal reflection at the other face ? The refractive index of the material of the prism is 1.524 |
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Answer» SOLUTION :sin `i_(E) = (1)/(N) = (1)/(1.524)= 0.6562 "" therefore i_(e) = 41^(@)` i.e., `r_(2) = i_(e) = 41^(@)` `r_(1) + r_(2) = A ` `r_(1) = A - r_(2) = 60 - 41 = 19^(@)` `(sin i_(1))/(sin r_(1))= n "" therefore sin i_(1) = n sin r_(1) = 1.524 sin 19^(@) = 0.4962 ` `i_(1) = sin^(1) (0.4962) i_(1) = 29^(@) 45. APPROX 30^(@)` . |
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