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At what distance from a convex mirror of focal length 2.5 m should a body stand so that his image has a height equal to half the original height ? The principal exis is perpendicular to the height. |
Answer» We have `m = -(upsilon)/(u) = (1)/(2)` or , `upsilon = (u)/(2).` Also, `(1)/(u) + (1)/(upsilon) = (1)/(f)` or , `(1)/(u) + (1)/(-u//2) = (1)/(2.5m)` or `- (1)/(u) = (1)/(2.5 m)` or u = - 2.5m. |
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