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At what temperature is the R.M.S. speed of gas molecules half the value at S.T.P.?A. 68.25 KB. 273 KC. 345 KD. 0 K |
Answer» Correct Answer - A `(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))` `(1)/(2)=sqrt((T_(2))/(T_(1)))` `(1)/(4)=(T_(2))/(T_(1))` `T_(2)=(T_(1))/(4)` `=(273)/(4)=68.25K` |
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