1.

At what temperature is the R.M.S. speed of gas molecules half the value at S.T.P.?A. 68.25 KB. 273 KC. 345 KD. 0 K

Answer» Correct Answer - A
`(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))`
`(1)/(2)=sqrt((T_(2))/(T_(1)))`
`(1)/(4)=(T_(2))/(T_(1))`
`T_(2)=(T_(1))/(4)`
`=(273)/(4)=68.25K`


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