1.

At what temperature is the root mean square velocity of gaseous hydrogen molecules is equal to that of oxygen molecules at `47^(@)C`?A. `20 K`B. `80 K`C. `-73 k`D. `3 k`

Answer» Correct Answer - A
For oxygen `V_(O_2) = sqrt((3RT_(O_2))/(M_(O_2)))` and
For hydrogen, `v_(H_2) = sqrt(3R(T_(H_2))/(M_(H_2)))`
According to problem `= sqrt((3RT_(O_2))/(M_(O_2))) = sqrt(3R(T_(H_2))/(M_(H_2)))`
`implies (T_(O_2))/(M_(O_2)) = (T_(H_2))/(M_(H_2)) implies (47+273)/(32) = (T_(H_2))/(M_(H_2))`
`implies T_(H_2) = (320)/(32)xx2 = 20K`.


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