1.

At what temperature liquid water will be in equilibrium with water vapour? `DeltaH_("vap")="40.73 kJ mol"^(-1),DeltaS_("vap")="0.109 kJ K"^(-1)"mol"^(-1)`A. 282.4 KB. 373.6 KC. 100 KD. 400 K

Answer» Correct Answer - B
At equilibrium `DeltaG=0" for "DeltaG=DeltaH-TDeltaS`
`"or T"=(DeltaH)/(DeltaS)=(40.73)/(0.109)="373.6 K"`


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