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At what temperature, the r.m.s. velocity of a gas measured at `50^(@)C` will become double ?A. 626KB. 1019KC. `200^(@)C`D. `1019^(@)C`

Answer» Correct Answer - D
`C _(rms)=sqrt((3RT)/(M))`
Where T is in kelvin scale.
For rms velocity to be doubled, T in kelvin scale must be raised 4 times. So it should be
`4 xx (50 +273) =1292K = 12920273=1019^(@)C`.


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