1.

At what temperature will oxygen molecules have the same root mean square speed as hydrogen molecules at 300 K ?

Answer»

4800 K
3600 K
2400 K
300 K.

Solution :Since ROOT MEAN square velocity of oxygen =rms value of HYDROGEN
`THEREFORE sqrt((3RT_(0))/(M_(0)))=sqrt((3RT_(H))/(M_(H)))`
`rArr T_(0) =T_(H) cdot (M_(0))/(M_(H))=300xx(32)/(2)=4800 k`
Thus, correct choice is (a).


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