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At what temperature will oxygen molecules have the same root mean square speed as hydrogen molecules at 300 K ? |
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Answer» 4800 K `THEREFORE sqrt((3RT_(0))/(M_(0)))=sqrt((3RT_(H))/(M_(H)))` `rArr T_(0) =T_(H) cdot (M_(0))/(M_(H))=300xx(32)/(2)=4800 k` Thus, correct choice is (a). |
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