1.

At what temperature will the average KE per molecule of a gas be exactly half its value at NTP?A. 150 KB. 136.5 KC. 273 KD. 546 K

Answer» Correct Answer - B
`E_(2)=(E_(1))/(2) and T_(1)=273`
`(E_(2))/(E_(1))=(T_(2))/(T_(1))`
`therefore T_(2)=(E_(2))/(E_(1))`
`T_(1)=(273)/(2)`
`therefore T_(2)=136.5K`


Discussion

No Comment Found

Related InterviewSolutions