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At what temperature will the average KE per molecule of a gas be exactly half its value at NTP?A. 150 KB. 136.5 KC. 273 KD. 546 K |
Answer» Correct Answer - B `E_(2)=(E_(1))/(2) and T_(1)=273` `(E_(2))/(E_(1))=(T_(2))/(T_(1))` `therefore T_(2)=(E_(2))/(E_(1))` `T_(1)=(273)/(2)` `therefore T_(2)=136.5K` |
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