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At what temperature will the R.M.S. velocity of a gas be double its value at N.T.P.?A. `273^(@)C`B. `546^(@)C`C. `819^(@)C`D. `1092^(@)C` |
Answer» Correct Answer - C `C_(2)=2C_(1)` `(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))` `(2C_(1))/(C_(1))=sqrt((T_(2))/(T_(1)))` `4=(T_(2))/(T_(1))` `T_(2)=4xx273=1092K` `T_(2)=1092-273` `=819C`. |
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