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At what temperature will the R.M.S. velocity of a gas be double its value at N.T.P.?A. `273^(@)C`B. `546^(@)C`C. `819^(@)C`D. `1092^(@)C`

Answer» Correct Answer - C
`C_(2)=2C_(1)`
`(C_(2))/(C_(1))=sqrt((T_(2))/(T_(1)))`
`(2C_(1))/(C_(1))=sqrt((T_(2))/(T_(1)))`
`4=(T_(2))/(T_(1))`
`T_(2)=4xx273=1092K`
`T_(2)=1092-273`
`=819C`.


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