1.

At what temperature will the rms speed of air molecules be double that of NTP?

Answer»

`519^(@)C`
`619^(@)C`
`719^(@)C`
`819^(@)C`

SOLUTION :As `v_(rms)=sqrt((3RT)/(M)),"At "T=T_(0),v_(rms)=sqrt((3RT_(0))/(M))`
But at TEMPERATURE T, `v_(rms)=2xxsqrt((3RT_(0))/(M))`
`implies sqrt((3RT)/(M))=2sqrt((3RT_(0))/(M))impliesT=4T_(0)`
`T=4xx273K=1092KthereforeT=819^(@)C`


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