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At what temperature , will the root mean square velocity on hydrogen be double of its value at `S.T.P`., pressure remaining constant ? |
Answer» Let `v_(1)` be the `r.m.s` velocity at `S.T.P.(=273K`) and `v_(2)` be the `r.m.s` velocity at unknown temperature `T_(2)`. `therefore (v_(1)^(2))/(v_(2)^(2)) = (T_(1))/(T_(2))` or `T_(2) =T_(1)[v_(2)/v_(1)]^(2) = 273xx(2)^(2) = 273xx4` `=1092 K = (1092-273) = 819^(@)C` |
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