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At `x = (A)/(4)`, what fraction of the mechanical energy is potential ? What fraction is kinetic ? Assume potential energy to be zero at mean position. |
Answer» Correct Answer - A `E = (1)/(2)kA^(2)` `U = (1)/(2)kx^(2) = (1)/(2)k((A)/(4))^(2)` `= (1)/(16)((1)/(2)kA^(2))` `= (1)/(16)E` Hence, `(1)/(16)` fraction is potential energy and `(15)/(16)` fraction is kinetic energy. |
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