Atomic number of H-like atom with ionization potential 122.4 V for n =

1.	Atomic number of H-like atom with ionization potential 122.4 V for n = 1 is
Answer» 1 2 3 4 Solution :The ionisation energy of a HYDROGEN ATOM is, `IE = (13.6 z^(2))/N^(2)` `THEREFORE z^(2) = (IE xx n^(2))/(13.6) = (122.4 xx (1)^(2))/(13.6) = 9 rArr z=3`

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Atomic number of H-like atom with ionization potential 122.4 V for n = 1 is

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