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Atomic radius and ionic radius of `F_(g)` and `F_(g)^-` are `72` and `136` pm prespectivley. Calculate the ratio and percentage increase in terms of volume during formation of `F_(g)^(-)` form `F_(g)` . |
Answer» Volume of ` F_((g)) = 4/3 pi xx (136)^3 = 10.54 xx10^6` Voleume of `F_((g))^(-) = (4)/(3) pi xx (136)^(3) =10.54 xx10^6` ` :. V_(F)^(-) =V_(F) xx [(136)/(72)]^3 =V-F xx 6.745` `:.` Increase in volume ` = [10.54 -1.56 ] xx 10^6 =8.98 xx10^6` ` :. %` increase = `(8,98 xx10^6) /(1 .56 xx10^6) xx 100=5. 75 xx10^2`. |
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