au)An electron beam is acccerated by a patenti diererce 1UO volts. wnatthe wavelength associated with the electron heani?(Mass of electron -9. 1X 10-3ikg, Charge of clectrou- 16 X 10

au)An electron beam is acccerated by a patenti diererce 1UO volts. wna

1.	au)An electron beam is acccerated by a patenti diererce 1UO volts. wnatthe wavelength associated with the electron heani?(Mass of electron -9. 1X 10-3ikg, Charge of clectrou- 16 X 10
Answer» <p>Energy acquired by the electron beam after being accelerated by a potential difference of 10000 volts = 10000 eV= 10000 × 1.602 × 10^-19 J( 1eV = 1.602 × 10^-19 J )= 1.602 × 10^-15 JThus, kinetic energy = 1.602 × 10^-15 J1/2 mv^2 = 1.602 × 10^-15 J1/2 × 9.1 × 10^-31 × v^2 = 1.602 × 10^-15 Jv^2 = 0.3521 × 10^16 v^2 = 35.21 × 10^14v = 5.934 × 10^7 ms-1Therefore, λ = h/mvλ = 6.626 × 10^−34/ 9.1 × 10^−31× 5.934 × 10^7λ = 0.1227 ×10^−10 m </p>