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InterviewSolution
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Auto manufactures study the collision of cars with mounted spring of different spring constant. Consider a car of mass 1500 kg moving with a speed of `36 kmh^(-1)` on a smooth road and colliding with a horizontally mounted spring of spring constant `7.5xx10^(3) Nm^(-1)`. Find the maximum compression of the spring . |
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Answer» At maximum compression, KE of car gets converted completely into PE of the spring. `KE " of " car =K=(1)/(2)mv^(2)=(1)/(2)xx1500xx10xx10` `(v=36xx(5)/(18)=10 ms^(-1))` `=7.5xx10^(4) J` At maximum compression `x_(m)`, PE,U of the spring =KE, K of car `U=(1)/(2)kx_(m)^(2)=7.5xx10^(4) Jimpliesx_(m)=sqrt((2xx7.5xx10^(4))/(7.5xx10^(3)))=4.47 m` |
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