1.

`ax^(2) +2hxy +by^(2) +2gx +2fy +x=0` तब ` (dy)/(dx) ` ज्ञात कीजिये |

Answer» `ax^(2) +2hxy +by^(2) +2gx +2fy +x=0`
दोनों पक्षों का x के सापेक्ष अवकलन करने पर
` a(d)/(dx) x^(2)+ 2h (d)/(dx) (xy)+b(d)/(dx) y^(2) +2g""(d)/(dx) x+ 2f (dy)/(dx) +0=0 `
` rArr " "2ax +2h [x (dy)/(dx) +y*1] +2by (dy)/(dx) +2g ""(dy)/(dx) +2g +2f"" (dy)/(dx)=0`
`rArr " "(ax + hy +g) +(dy)/(dx) (hx +by+f)=0`
` rArr " "(dy)/(dx) =-((ax+hy+g)/(hx +by +f))`


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