1.

निम्न फलन का अवकल गुणांक ज्ञात कीजिये -` x^(y) +y^(x)=1 `

Answer» Correct Answer - ` " " (-y^(x)log y+ yx^(y-1))/(x^(y) log x + xy^(x-1))`
माना ` " " y=y_1+ y_2 ` जहाँ ` y_1 -x^(y) ` और ` y_2 =y^(x)`
अब `" "y_ 1 =x^(y)" "rArr log y_1 =ylog x `
`rArr " "(dy_1)/(dx) =y_1 ((y)/(x)+ log x (dy)/(dx))`
` " "y_2 =y^(x)`
`rArr " "log y_2 =x log y `
`rArr (dy_2)/(dx) =y_2 ((x)/(y) (dy)/(dx) +log y)`


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