InterviewSolution
Saved Bookmarks
| 1. |
निम्न फलन का अवकल गुणांक ज्ञात कीजिये -` x^(y) +y^(x)=1 ` |
|
Answer» Correct Answer - ` " " (-y^(x)log y+ yx^(y-1))/(x^(y) log x + xy^(x-1))` माना ` " " y=y_1+ y_2 ` जहाँ ` y_1 -x^(y) ` और ` y_2 =y^(x)` अब `" "y_ 1 =x^(y)" "rArr log y_1 =ylog x ` `rArr " "(dy_1)/(dx) =y_1 ((y)/(x)+ log x (dy)/(dx))` ` " "y_2 =y^(x)` `rArr " "log y_2 =x log y ` `rArr (dy_2)/(dx) =y_2 ((x)/(y) (dy)/(dx) +log y)` |
|