InterviewSolution
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InterviewSolution
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Ax^2+bx+c = 0 Has Two Roots X1 And X2. If Mode X1 = Mode X2, Then? |
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Answer» mod X1 = mod X2 => x1 & x2 have same VALUE but opposite in sign. in this CASE b=0 eqn is ax^2+c = 0 => x=sqrt(-c/a) for x to be real (-c/a) should +ve => c & a are of opposite sign so c>a or a>c for ex x^2-4=0 => x1=-2, x2=2 & modx1=modx2=2 [a>c] or may -x^2+4=0 => x1=-2,x2=2 & modx1=modx2=2 (d) none mod x1 = mod x2 => x1 & x2 have same value but opposite in sign. in this case b=0 eqn is ax^2+c = 0 => x=sqrt(-c/a) for x to be real (-c/a) should +ve => c & a are of opposite sign so c>a or a>c for ex x^2-4=0 => x1=-2, x2=2 & modx1=modx2=2 [a>c] or may -x^2+4=0 => x1=-2,x2=2 & modx1=modx2=2 (d) none |
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