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B^(2)/(mu_(0)), where B is magnetic induction and mu_(0) is permeability of free space, has the same dimensions as : |
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Answer» energy Now `(B^(2))/(mu_(0))=(M^(2)T^(-4)A^(-2))/(MLT^(-2)A^(-2))` `=[ML^(-1)T^(-2)]` =energy density. Hence CORRECT CHOICE is `(b)`. |
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