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(b+c)(b-c)+(c+a)(c-a)+(a+b)(a-b) |
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Answer» Step-by-step EXPLANATION:(a+b)(a-b)+(b+c)(b-c)+(c+a)(c-a, =(a²-b²)+(b²-c²)+(c²-a²), =(a²-b²+b²-c²+c²-a²), In this case, each variable cancels it's NEGATIVE version. = 0 |
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