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InterviewSolution
| 1. |
(B) Charle's lawAvogadro's lawEqual masses of methane and oxygen are mispressure exerted by oxygen isIIT -8111 273D) 3 298(C) 2/3 |
| Answer» <p>If x g of both oxygen and methane are mixed then : Mole of oxygen = x/32 Mole of methane = x/16 ⇒ mole fraction of oxygen = (x/32)/(x/32 + x/16) = 1/3 According to law of partial pressure Partial pressure of oxygen (po2) = mole-fraction × total pressure ⇒ 〖Po〗_2/p = 1/3</p><p>Option A is correct </p> | |