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b) increasesdecreasesD) becomes zero5)When a mercury drop of radius R, breaks into n droplets of equal size, the radius (t) of each droplet is71C) r = Rm1/3n1/3D)6)The surface tension of a liour. İsar1n |
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Answer» Relation between big drop of Radius R and radius of small n drops of radius r is R^3 = nr^3(volume remains equal) r = R/n^1/3 (B) is correct option |
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