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B is 50% of A and C is 16.67% of B and the sum of all three numbers is 38. Find the smallest number.1). 12). 43). 64). 2 |
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Answer» LET A = a so B = 50% of a = a/2 and C = 16.67% of a/2 = 1/6 × a/2 = a/12 A + B + C = a + a/2 + a/12 = 38 ⇒ 19a/12 = 38 ⇒ a = 24 ∴ SMALLEST number, C = a/12 = 24/12 = 2 |
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