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(b) Obtain the expression for the capacitance of a parallel plate capacitor. |
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Answer» Solution :Each PLATE of the capacitor has area A and the plates are separated by distance d. If V is potential DIFFERENCE between two plates, then V=Ed If `sigma` is surface charge DENSITY then `E=(sigma)/(epsi_(0))` `impliesV=(sigma)/(E_(0))d` Now, `s=q//\AimpliesV=(sigma)/(E_(0)A)d`  If C is capacitance then `C=(q)/(V)=((q)/(QD))/(in_(0)A)impliesC=(in_(0)A)/(d)`. |
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