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Balance the equation by ion electron method. PbO2 + Cl– → ClO– + [Pb(OH)3]– in basic solution. |
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Answer» Here 2e– + PbO2 → [Pb(OH)3]– 2H2O + 2e–PbO22 → [Pb(OH)3] + OH– …(i) 2OH + Cl– → ClO– + 2e– + H2O …(ii) Add (i) & (ii) PbO2 + OH– + Cl– + H2O → [Pb(OH)3]– + ClO– |
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