1.

Balance the equation by ion electron method. PbO2 + Cl– → ClO– + [Pb(OH)3]– in basic solution.

Answer»

Here 

2e– + PbO2 → [Pb(OH)3]– 

2H2O + 2e–PbO22 → [Pb(OH)3] + OH– …(i) 

2OH + Cl– → ClO– + 2e– + H2O …(ii)

Add (i) & (ii) 

PbO2 + OH– + Cl– + H2O → [Pb(OH)3]– + ClO–



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