Bandwidth (b) Of An Am Signal Is Given By?

1.	Bandwidth (b) Of An Am Signal Is Given By?
Answer» Bandwidth of the AM WAVE is the difference in the TWO extreme frequencies of the AM signal. It is GIVEN by B = (ωc + ωm)- (ωc - ωm) = ωm i.e., the bandwidth of the AM wave is twice the highest frequency present in the modulating signal. Bandwidth of the AM wave is the difference in the two extreme frequencies of the AM signal. It is given by B = (ωc + ωm)- (ωc - ωm) = ωm i.e., the bandwidth of the AM wave is twice the highest frequency present in the modulating signal.

Answer»

Bandwidth of the AM WAVE is the difference in the TWO extreme frequencies of the AM signal. It is GIVEN by

B = (ωc + ωm)- (ωc - ωm)
= ωm

i.e., the bandwidth of the AM wave is twice the highest frequency present in the modulating signal.

Bandwidth of the AM wave is the difference in the two extreme frequencies of the AM signal. It is given by

B = (ωc + ωm)- (ωc - ωm)
= ωm

i.e., the bandwidth of the AM wave is twice the highest frequency present in the modulating signal.

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