1.

bara^(1)xxbarb^(1)+barb^(1)xxbarc^(1)+barc^(1)xxbara^(1)=

Answer»

`(bara+barb+barc)/([BARABARBBARC])`
`(bara-barb-barc)/([barabarbbarc])`
`(bara+barb+barc)/([barbbarabarc])`
`(bara+barb+barc)/(2[barabarbbarc])`

ANSWER :A


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