1.

[barbbarcbarbxxbarc]+{barb.barc}^(2)=

Answer»

`(BARB+BARC)^(2)`
`ABS(barb)^(2)+abs(barc)^(2)`
`abs(barb)+abs(barc)`
`abs(barb)^(2)abs(barc)^(2)`

ANSWER :D


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