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InterviewSolution
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Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles. |
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Answer» Let the base height and area of the first triangle be `b_(1),h_(1)` and `A_(1)` respectively. Let the base, height and area of the second triangle be `b_(2),h_(2)` and `A_(2)` respectively. `b_(1)=9,h_(1)=5,b_(2)=10` and `h_(2)=6`. The ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights. `(A_(1))/(A_(2))=(b_(1)xxh_(1))/(b_(2)xxh_(2))` `:.(A_(1))/(A_(2))=(9xx5)/(10xx6):.(A_(1))/(A_(2))=3/4` The ratio of the areas of the triangles is 3:4. |
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