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Below Is A Pseudo Code Read X While(x < 60) Write X X = X*3 |
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Answer» The last NUMBER in the sequence is 54, what has the USER ENTERED as the initial value of x Given Last value int seq. = 54. and in every Loop result multiplied By 3. So By Backward Approach 54/3=18 => 18/3=6 => 6/3=2. So, The Starting Value Is 2 The last number in the sequence is 54, what has the user entered as the initial value of x Given Last value int seq. = 54. and in every Loop result multiplied By 3. So By Backward Approach 54/3=18 => 18/3=6 => 6/3=2. So, The Starting Value Is 2 |
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