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Between the plates of a parallel plate condenser, a plate of thickness `t_(1)` and dielectric constant `k_(1)` is placed. In the rest of the space, there is another plate of thickness `t_(2)` and dielectric constant `k_(2)`. The potential difference across the condenser will beA. `Q/(Aepsilon_(0))((t_(1))/(k_(1))+(t_(2))/(k_(2)))`B. `(epsilon_(0)Q)/A((t_(1))/(k_(1))+(t_(2))/(k_(2)))`C. `Q/(Aepsilon_(0))((k_(1))/(t_(1))+(k_(2))/(t_(2)))`D. `(epsilon_(0)Q)/A(k_(1)t_(1)+k_(2)t_(2))` |
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Answer» Correct Answer - A `1/(C_(eq))=(t_(1))/(k_(1)epsilon_(0)A)+(t_(2))/(k_(2)epsilon_(0)A)` `V=Q/(C_(eq))=Q/(epsilon_(0)A)((t_(1))/(K_(1))+(t_(2))/(K_(2)))` |
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