ɴ :-Given That :- → Length of Rectangular Aluminium STRIP = 8(3/4) = (35/4) cm.→ Diameter of Circles To be CUT = 1(1/4) = (5/4) cm.Now, we can cut circles upto Length of Rectangular Aluminium Strip. So, → TOTAL Circles cut = (35/4) ÷ (5/4) = (35/4) * (4/5) = 7 Circles (Ans.) ______________________Now, → Length of Rectangular Aluminium Strip = (35/4)cm.→ Breadth of Rectangular Aluminium Strip = (5/4) cm.So, → Area of Rectangular Aluminium Strip = Length * Breadth = (35/4) * (5/4) = (175/16)cm². And,→ Diameter of Each Circle = (5/4) cm.→ Radius of Each circle = (5/4) * (1/2) = (5/8) cm.So, → Area of one Circle = π * (Radius)² = (22/7) * (5/8)² = (22/7) * (25/64) cm². Therefore, → Area of 7 such Circles = 7 * (22/7) * (25/64) = (550/64) cm². ______________________Hence, → The wastage of Aluminium Strip = Area of Rectangular Aluminium Strip - Area of 7 circles → The wastage of Aluminium Strip = (175/16) - (550/64) = (175*4 - 550)/64 = (150/64) = (75/32) = 2(11/32)cm². (Ans.)