1.

Binding energy per nucleon of ._1H^2 and ._2He^4 are 1.1 MeV and 7.0 MeV respectively. Energy released in the process ._1H^2 + ._1H^2 = ._2He^4 is -

Answer»

20.8 MeC
16.6 MeV
25.2 MeV
23.6 MeV

Answer :D


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