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Biologically useful technetium nuclei (with atomic weight 99) have a half life of 6 hrs. A solution containing `10^(-12)` g of this is injected into the bladder of a patient. Find its activity in the beginning and after one hour. |
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Answer» Correct Answer - `7.026xx10^(8)hr^(-1); 6.26xx10^(8)hr^(-1)` Here, `T=6hrs., lambda=0.693/T=0.693/6 hr^(-1)` No. of atoms in `10^(-12)g` at t=0 `N_(0)=(6.023xx10^(23))/99xx10^(-12)=6.08xx10^(9)` Activity of the sample at t=0 `((dN)/(dt))_(0)=lambda N_(0)=0.693/6xx6.08xx10^(9)hr^(-1)` `=7.026xx10^(8)hr^(-1)` form `N/(N_(0))=(1/2)^(t//T)=(1/2)^(1//6)` calculate `N=5.423xx10^(9)` `:. ((dN)/(dt))_(t)=lambdaN=0.693/6xx5.423xx10^(9)` `=6.26xx10^(8)hr^(-1)` |
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