1.

Black body at a temperature of `1640K` has the wavelength corresponding to maximum emission equal to `1.75mu m` Assuming the moon to be a perfectly black body the temperature of the moon if the wavelength corresponding to maximum emission is `14.35mum` is .A. 100 KB. 150 KC. 200 KD. 250 K

Answer» Correct Answer - C
`(T_(2))/(T_(1))=(lamda_(m_(1)))/(lamda_(m_(2)))=(1.75)/(14.35)`
`T_(2)=(1.75)/(14.35)xx1640=200K`


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