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Black body at a temperature of `1640K` has the wavelength corresponding to maximum emission equal to `1.75mu m` Assuming the moon to be a perfectly black body the temperature of the moon if the wavelength corresponding to maximum emission is `14.35mum` is .A. 100 KB. 150 KC. 200 KD. 250 K |
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Answer» Correct Answer - C `(T_(2))/(T_(1))=(lamda_(m_(1)))/(lamda_(m_(2)))=(1.75)/(14.35)` `T_(2)=(1.75)/(14.35)xx1640=200K` |
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