Block A is released from rest from wedge B. find out velocity of the wedge 'C' when the bloack A slide down completely after climbing up on it. All surfces are smooth. Block A, wedge B and wedge C are at rest initially.

Block A is released from rest from wedge B. find out velocity of the w

1.	Block A is released from rest from wedge B. find out velocity of the wedge 'C' when the bloack A slide down completely after climbing up on it. All surfces are smooth. Block A, wedge B and wedge C are at rest initially.
Answer» `sqrt(2gH)` `sqrt(gH)` `sqrt((16gh)/(27))` `sqrt((4gH)/(9))` SOLUTION :When A slide down from the wedge B by conservatio of momentum and ENERGY `0=mv_(A)-2mv_(B)` `(1)/(2)2mv_(B)^(2)+(1)/(2)mv_(A)^(2)=MGH` When block A climbs up and then climbs down from C. By CONSERVATION of momentum and energy velocity of with `C=(2m)/(m+2m)V_(A)`

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Block A is released from rest from wedge B. find out velocity of the wedge 'C' when the bloack A slide down completely after climbing up on it. All surfces are smooth. Block A, wedge B and wedge C are at rest initially.

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