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Block `A` of mass `1 kg` is placed on the rough surface of block `B` of mass `3 kg`. Block `B` is placed on smooth horizontal surface. Blocks are given the velocities as shown. Find net work done by the frictional force. [in `(-) ve J`]. . |
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Answer» Correct Answer - `6` `(1+3)v = (1) (8) +(3)(4) = 20 , v = 5 m//sec` for block `A, W_(f) = (1)/(2)(1) (5^(2) -8^(2)) = -(39)/(2) J` for block `B, W_(f) =(1)/(2)(3)(5^(2) -4^(2)) = +(27)/(2) J` net work done by friction `= -6 J`. |
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