BlockA of mass 2 kg is placed over block B of mass8 kg .The combination is placed over a rough horizonatal surface .Cofficient of friction between B and the floor is 0.5 .Coefficient of friction berween A and B is 0.4 .A horizontal force of 10 N is applied on block B .The force of friction between A and B is (g=10 ms^(-2))

BlockA of mass 2 kg is placed over block B of mass8 kg .The combinatio

1.	BlockA of mass 2 kg is placed over block B of mass8 kg .The combination is placed over a rough horizonatal surface .Cofficient of friction between B and the floor is 0.5 .Coefficient of friction berween A and B is 0.4 .A horizontal force of 10 N is applied on block B .The force of friction between A and B is (g=10 ms^(-2))
Answer» 100N 40N 50N zero Solution :Force of friction between BLOCK B and ground is `F_(f)=muR = 0.5 xx 10 xx 10 = 50 N.` Since force applied on B is less than frictional force so block B will not MOVE w.r.t. ground. So there is no relative motion between block B and block A. So frictional force between A and B is zero. :. Correct choice is (d).

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