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body starts from rest and is in uniformly accelerated in a straight line at the rate of 5 m/s .Find the velocity of the body at the end of 10 seconds. |
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Answer» -step explanation:The initial VELOCITY travelled is 625mThe accleration is α=10m/s 2 The TIME is t=5sApply the equation of motionv=u+atThe velocity is v=0+10.5=50m/s.The distance travelled in the FIRST 5s iss=ut+ 21 at 2 =0.5+ 21 .10.5 2 =125mThedistancetravelledinthefollowing10siss 1 =ut 1 =50.10=500mThetotaldistancetravelledisd=s+s 1 =125+500=625m |
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