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bomb moving with velocity 40i + 50j + 25k m/s explodes into pieces of mass ratio 1 : 4. If the small piece goes out with velocity 200i +70j -15k m/s, find the velocity of larger piece after explosion.

Answer»

SOLUTION :Let 5m be mass of bomb. The largest PIECE will have mass 4m. Using principle of momentum CONSERVATION,
`5m(40hati + 50hatj - 25hatk) =m(200hati + 70hatj-15hatk) + 4mvecv`
Which gives `vecv =(180hatj + 140hatk)/4 =(45hatj + 35hatk)`


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