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| 1. |
Bond angle in "PH"_(4)^(" "+) is higher than that in "PH"_(3). Why ? |
| Answer» Solution :In `PH_(4)^(+)`, phosphorous undergo `SP^(3)` hybridization, but in `PH_(3)` phasphorous uses PURE p-oribitals for bonding. Hence BOND angle in `PH_(3)` is nearly `90^(@)`. | |