Bond dissociation energy of`CH_(3)-H`bond is`103Kcalmol^(-1)`and`0.055cal//g ` respectively ,If specific heat of iodine is `24cal//g` at `200^(@)`,Calcualte its value at`250^(@)C` isA. `3.61Kcalmol^(-1)`B. `-3.61Kcalmol^(-1)`C. `33.61Kcalmol^(-1)`D. `-33.61Kcalmol^(-1)`

Bond dissociation energy of`CH_(3)-H`bond is`103Kcalmol^(-1)`and`0.055

1.	Bond dissociation energy of`CH_(3)-H`bond is`103Kcalmol^(-1)`and`0.055cal//g ` respectively ,If specific heat of iodine is `24cal//g` at `200^(@)`,Calcualte its value at`250^(@)C` isA. `3.61Kcalmol^(-1)`B. `-3.61Kcalmol^(-1)`C. `33.61Kcalmol^(-1)`D. `-33.61Kcalmol^(-1)`
Answer» Correct Answer - C `CH_(4)(g)=CH_(3)(g)+H("atom,g")` `(DeltaH_(f))_(CH_(3),H)CH_(3)-H=103` `=DeltaH_(f)(CH_(3),g)+DeltaH_(f)(H "atom, g")-DeltaH_(f)(CH_(4),g)` `(DeltaH_(f))_(CH_(3)g)=103-(103)/(2)+(-17.889)=33.611Kcalmol^(-1)` `:.` Heat of formation of methyl radical is `DeltaH=33.611Kcalmol^(-1)`

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Bond dissociation energy of`CH_(3)-H`bond is`103Kcalmol^(-1)`and`0.055cal//g ` respectively ,If specific heat of iodine is `24cal//g` at `200^(@)`,Calcualte its value at`250^(@)C` isA. `3.61Kcalmol^(-1)`B. `-3.61Kcalmol^(-1)`C. `33.61Kcalmol^(-1)`D. `-33.61Kcalmol^(-1)`

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