Bond energies of `N-=N, H-H` and `N-H` bonds are 945,463 & 391 kJ `mol^(-1)` respectively, the enthalpy of the following reactions is : `N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)`

Bond energies of `N-=N, H-H` and `N-H` bonds are 945,463 & 391 kJ `mol

1.	Bond energies of `N-=N, H-H` and `N-H` bonds are 945,463 & 391 kJ `mol^(-1)` respectively, the enthalpy of the following reactions is : `N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)`
Answer» Correct Answer - `+93 KJ` `DeltaH = 6xxDeltaH_(N-H) - DeltaH_(N-N) - 3DeltaH_(H-H) = 93 KJ`

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Bond energies of `N-=N, H-H` and `N-H` bonds are 945,463 & 391 kJ `mol^(-1)` respectively, the enthalpy of the following reactions is : `N_(2)(g)+3H_(2)(g)rarr2NH_(3)(g)`

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