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Bond order of nitric oxide isA. 1B. 2.5C. 2D. 1.5 |
Answer» Correct Answer - B E.C. of NO = KK`[sigma(2s)]^(2)[sigma^**(2s)]^2 [sigma(2p_z)]^2 [pi(2p_x)]^2 [pi(2p_y)]^2 [pi^**(2p_x)]^1` `therefore` Bond order =`1/2(8-3)=5/2=2.5` |
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